Radioligand binding

EF Elisabetta De Filippo
VN Vigneshwaran Namasivayam
LZ Lukas Zappe
AE Ali El-Tayeb
AS Anke C. Schiedel
CM Christa E. Müller
ask Ask a question
Favorite

Competition experiments were performed with [3H]CGS21680 and [3H]NECA in a final volume of 400 μl. The vial contained 10 μl of dissolved test compound in DMSO, 90 μl of Tris buffer (50 mM, pH 7.4), 100 μl of MgCl2 solution (final concentration: 10 mM), 100 μl of radioligand solution (final radioligand concentration: [3H]CGS21680, 5 nM; [3H]NECA, 3 nM), and 100 μl of membrane preparation (70–150 μg/vial), which was previously incubated with 2 U of adenosine deaminase per milligram of protein for 20 min. Total binding was measured in the absence of test compound, while non-specific binding was determined in the presence of 50 μM NECA in experiments with [3H]CGS21680, and 100 μM of N6-(R)-(2-phenylisopropyl)adenosine (R-PIA) in experiments with [3H]NECA. After incubation ([3H]CGS21680, 1 h; [3H]NECA, 3 h), the assay mixture was filtered through GF/B glass fiber filters using a Brandel harvester (Brandel, Gaithersburg, USA). The filters were washed three times with 300 μl ice-cold Tris buffer (50 mM, pH 7.4), transferred into scintillation vials and incubated for 6 h with 2.5 ml of scintillation cocktail LUMASAFE. The vials were then counted in a liquid scintillation counter (Tricarb 2900TR, Perkin Elmer, Rodgau, Germany). Independent experiments were performed in duplicates. In the homologous competitive binding, a single concentration of radiolabeled ligand and various concentrations of the identical unlabeled ligand were used. For the analysis, it is assumed that the system is at equilibrium and that both hot and cold ligands bind with identical affinities. Thus, the KD and Ki values are identical. With the Cheng and Prussoff equation, the Ki value is calculated from the IC50 resulting in Kd = Ki = IC50—[radioligand].

Do you have any questions about this protocol?

Post your question to gather feedback from the community. We will also invite the authors of this article to respond.

post Post a Question
0 Q&A